How can I convert a datetime object to milliseconds since epoch (unix time) in Python?
我有一个python
我该怎么做？
我觉得最简单的方法是
1 2 3 4 5 6 | import datetime epoch = datetime.datetime.utcfromtimestamp(0) def unix_time_millis(dt): return (dt - epoch).total_seconds() * 1000.0 |
。
在python 3.3中，添加新方法。
1 | datetime.timestamp() |
。
https://docs.python.org/3.3/library/datetime.html datetime.datetime.timestamp
1 2 3 4 | >>> import datetime >>> # replace datetime.datetime.now() with your datetime object >>> int(datetime.datetime.now().strftime("%s")) * 1000 1312908481000 |
或时间模块的帮助(不带日期格式)：
1 2 3 4 | >>> import datetime, time >>> # replace datetime.datetime.now() with your datetime object >>> time.mktime(datetime.datetime.now().timetuple()) * 1000 1312908681000.0 |
号
在http://pleac.sourceforge.net/pleac_python/datesandtimes.html的帮助下回答
文档：
time.mktime 。- 江户十一〔一〕号
针对
。
你可以用德洛伦在太空和时间旅行！
1 2 3 4 | import datetime import delorean dt = datetime.datetime.utcnow() delorean.Delorean(dt, timezone="UTC").epoch |
。
http://delorean.readthedocs.org/en/latest/quickstart.htmlnbsp；
我就是这样做的：
1 2 3 4 5 6 7 | from datetime import datetime from time import mktime dt = datetime.now() sec_since_epoch = mktime(dt.timetuple()) + dt.microsecond/1000000.0 millis_since_epoch = sec_since_epoch * 1000 |
1 2 3 4 5 6 7 8 9 10 11 12 | from datetime import datetime from calendar import timegm # Note: if you pass in a naive dttm object it's assumed to already be in UTC def unix_time(dttm=None): if dttm is None: dttm = datetime.utcnow() return timegm(dttm.utctimetuple()) print"Unix time now: %d" % unix_time() print"Unix timestamp from an existing dttm: %d" % unix_time(datetime(2014, 12, 30, 12, 0)) |
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 | >>> import datetime >>> import time >>> import calendar >>> #your datetime object >>> now = datetime.datetime.now() >>> now datetime.datetime(2013, 3, 19, 13, 0, 9, 351812) >>> #use datetime module's timetuple method to get a `time.struct_time` object.[1] >>> tt = datetime.datetime.timetuple(now) >>> tt time.struct_time(tm_year=2013, tm_mon=3, tm_mday=19, tm_hour=13, tm_min=0, tm_sec=9, tm_wday=1, tm_yday=78, tm_isdst=-1) >>> #If your datetime object is in utc you do this way. [2](see the first table on docs) >>> sec_epoch_utc = calendar.timegm(tt) * 1000 >>> sec_epoch_utc 1363698009 >>> #If your datetime object is in local timeformat you do this way >>> sec_epoch_loc = time.mktime(tt) * 1000 >>> sec_epoch_loc 1363678209.0 |
。
[1]http://docs.python.org/2/library/datetime.html datetime.date.timetuple
[2]http://docs.python.org/2/library/time.html网站
下面是另一种形式的解决方案，它对时间对象进行了规范化：
1 2 3 4 5 | def to_unix_time(timestamp): epoch = datetime.datetime.utcfromtimestamp(0) # start of epoch time my_time = datetime.datetime.strptime(timestamp,"%Y/%m/%d %H:%M:%S.%f") # plugin your time object delta = my_time - epoch return delta.total_seconds() * 1000.0 |
这是我根据上面的答案做的一个函数
1 2 3 | def getDateToEpoch(myDateTime): res = (datetime.datetime(myDateTime.year,myDateTime.month,myDateTime.day,myDateTime.hour,myDateTime.minute,myDateTime.second) - datetime.datetime(1970,1,1)).total_seconds() return res |
号
您可以这样包装返回值：str(int(res))返回它时不带十进制值，用作字符串或只返回int(不带str)
1 2 | import time seconds_since_epoch = time.mktime(your_datetime.timetuple()) * 1000 |
熊猫代码：
1 2 3 4 | import pandas def to_millis(dt): return int(pandas.to_datetime(dt).value / 1000000) |
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将日期时间转换为unixtimestampmillis的另一个解决方案。
1 2 3 4 5 6 7 8 9 | private static readonly DateTime UnixEpoch = new DateTime(1970, 1, 1, 0, 0, 0, DateTimeKind.Utc); public static long GetCurrentUnixTimestampMillis() { DateTime localDateTime, univDateTime; localDateTime = DateTime.Now; univDateTime = localDateTime.ToUniversalTime(); return (long)(univDateTime - UnixEpoch).TotalMilliseconds; } |
。