关于python:如何在matplotlib中绘制渐变色线?

How to plot a gradient color line in matplotlib?

为了以一般的形式陈述它,我正在寻找一种使用matplotlib将具有渐变色线的多个点连接起来的方法,但是在任何地方都找不到。
更具体地说,我正在绘制一条带有一条色线的2D随机游动图。 但是,由于这些点具有相关的顺序,因此我想查看该图并查看数据已移至何处。 渐变色线可以解决问题。 或透明度逐渐变化的线。

我只是想改善数据的虚拟化。 看看R的ggplot2软件包产生的这张精美图片。我正在matplotlib中寻找相同的图片。 谢谢。

enter image description here


我最近以类似的要求回答了一个问题(使用matplotlib创建了20多种独特的图例颜色)。我在那里展示了您可以映射将线条绘制到颜色图所需的颜色循环。您可以使用相同的过程为每对点获取特定的颜色。

您应该仔细选择颜色图,因为如果颜色图是彩色的,则沿线的颜色过渡可能会显得很剧烈。

或者,您可以更改每个线段的Alpha,范围从0到1。

下面的代码示例中包含一个例程(highResPoints),用于扩展您的随机游走所拥有的点数,因为如果您的点数太少,则过渡可能看起来很困难。我最近提供的另一个答案启发了这段代码:https://stackoverflow.com/a/8253729/717357

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import numpy as np
import matplotlib.pyplot as plt

def highResPoints(x,y,factor=10):
    '''
    Take points listed in two vectors and return them at a higher
    resultion. Create at least factor*len(x) new points that include the
    original points and those spaced in between.

    Returns new x and y arrays as a tuple (x,y).
    '''


    # r is the distance spanned between pairs of points
    r = [0]
    for i in range(1,len(x)):
        dx = x[i]-x[i-1]
        dy = y[i]-y[i-1]
        r.append(np.sqrt(dx*dx+dy*dy))
    r = np.array(r)

    # rtot is a cumulative sum of r, it's used to save time
    rtot = []
    for i in range(len(r)):
        rtot.append(r[0:i].sum())
    rtot.append(r.sum())

    dr = rtot[-1]/(NPOINTS*RESFACT-1)
    xmod=[x[0]]
    ymod=[y[0]]
    rPos = 0 # current point on walk along data
    rcount = 1
    while rPos < r.sum():
        x1,x2 = x[rcount-1],x[rcount]
        y1,y2 = y[rcount-1],y[rcount]
        dpos = rPos-rtot[rcount]
        theta = np.arctan2((x2-x1),(y2-y1))
        rx = np.sin(theta)*dpos+x1
        ry = np.cos(theta)*dpos+y1
        xmod.append(rx)
        ymod.append(ry)
        rPos+=dr
        while rPos > rtot[rcount+1]:
            rPos = rtot[rcount+1]
            rcount+=1
            if rcount>rtot[-1]:
                break

    return xmod,ymod


#CONSTANTS
NPOINTS = 10
COLOR='blue'
RESFACT=10
MAP='winter' # choose carefully, or color transitions will not appear smoooth

# create random data
np.random.seed(101)
x = np.random.rand(NPOINTS)
y = np.random.rand(NPOINTS)

fig = plt.figure()
ax1 = fig.add_subplot(221) # regular resolution color map
ax2 = fig.add_subplot(222) # regular resolution alpha
ax3 = fig.add_subplot(223) # high resolution color map
ax4 = fig.add_subplot(224) # high resolution alpha

# Choose a color map, loop through the colors, and assign them to the color
# cycle. You need NPOINTS-1 colors, because you'll plot that many lines
# between pairs. In other words, your line is not cyclic, so there's
# no line from end to beginning
cm = plt.get_cmap(MAP)
ax1.set_color_cycle([cm(1.*i/(NPOINTS-1)) for i in range(NPOINTS-1)])
for i in range(NPOINTS-1):
    ax1.plot(x[i:i+2],y[i:i+2])


ax1.text(.05,1.05,'Reg. Res - Color Map')
ax1.set_ylim(0,1.2)

# same approach, but fixed color and
# alpha is scale from 0 to 1 in NPOINTS steps
for i in range(NPOINTS-1):
    ax2.plot(x[i:i+2],y[i:i+2],alpha=float(i)/(NPOINTS-1),color=COLOR)

ax2.text(.05,1.05,'Reg. Res - alpha')
ax2.set_ylim(0,1.2)

# get higher resolution data
xHiRes,yHiRes = highResPoints(x,y,RESFACT)
npointsHiRes = len(xHiRes)

cm = plt.get_cmap(MAP)

ax3.set_color_cycle([cm(1.*i/(npointsHiRes-1))
                     for i in range(npointsHiRes-1)])


for i in range(npointsHiRes-1):
    ax3.plot(xHiRes[i:i+2],yHiRes[i:i+2])

ax3.text(.05,1.05,'Hi Res - Color Map')
ax3.set_ylim(0,1.2)

for i in range(npointsHiRes-1):
    ax4.plot(xHiRes[i:i+2],yHiRes[i:i+2],
             alpha=float(i)/(npointsHiRes-1),
             color=COLOR)
ax4.text(.05,1.05,'High Res - alpha')
ax4.set_ylim(0,1.2)



fig.savefig('gradColorLine.png')
plt.show()

此图显示了四种情况:

enter image description here


请注意,如果您有很多点,则对每个线段调用plt.plot可能会很慢。使用LineCollection对象更有效。

使用colorline配方,您可以执行以下操作:

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import matplotlib.pyplot as plt
import numpy as np
import matplotlib.collections as mcoll
import matplotlib.path as mpath

def colorline(
    x, y, z=None, cmap=plt.get_cmap('copper'), norm=plt.Normalize(0.0, 1.0),
        linewidth=3, alpha=1.0):
   """
    http://nbviewer.ipython.org/github/dpsanders/matplotlib-examples/blob/master/colorline.ipynb
    http://matplotlib.org/examples/pylab_examples/multicolored_line.html
    Plot a colored line with coordinates x and y
    Optionally specify colors in the array z
    Optionally specify a colormap, a norm function and a line width
   """


    # Default colors equally spaced on [0,1]:
    if z is None:
        z = np.linspace(0.0, 1.0, len(x))

    # Special case if a single number:
    if not hasattr(z,"__iter__"):  # to check for numerical input -- this is a hack
        z = np.array([z])

    z = np.asarray(z)

    segments = make_segments(x, y)
    lc = mcoll.LineCollection(segments, array=z, cmap=cmap, norm=norm,
                              linewidth=linewidth, alpha=alpha)

    ax = plt.gca()
    ax.add_collection(lc)

    return lc


def make_segments(x, y):
   """
    Create list of line segments from x and y coordinates, in the correct format
    for LineCollection: an array of the form numlines x (points per line) x 2 (x
    and y) array
   """


    points = np.array([x, y]).T.reshape(-1, 1, 2)
    segments = np.concatenate([points[:-1], points[1:]], axis=1)
    return segments

N = 10
np.random.seed(101)
x = np.random.rand(N)
y = np.random.rand(N)
fig, ax = plt.subplots()

path = mpath.Path(np.column_stack([x, y]))
verts = path.interpolated(steps=3).vertices
x, y = verts[:, 0], verts[:, 1]
z = np.linspace(0, 1, len(x))
colorline(x, y, z, cmap=plt.get_cmap('jet'), linewidth=2)

plt.show()

enter image description here


注释太长,因此只想确认LineCollection比行子段上的for循环快得多。

LineCollection方法在我手中要快得多。

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# Setup
x = np.linspace(0,4*np.pi,1000)
y = np.sin(x)
MAP = 'cubehelix'
NPOINTS = len(x)

我们将针对上面的LineCollection方法测试迭代绘图。

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%%timeit -n1 -r1
# Using IPython notebook timing magics
fig = plt.figure()
ax1 = fig.add_subplot(111) # regular resolution color map
cm = plt.get_cmap(MAP)
for i in range(10):
    ax1.set_color_cycle([cm(1.*i/(NPOINTS-1)) for i in range(NPOINTS-1)])
    for i in range(NPOINTS-1):
        plt.plot(x[i:i+2],y[i:i+2])

1 loops, best of 1: 13.4 s per loop

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%%timeit -n1 -r1
fig = plt.figure()
ax1 = fig.add_subplot(111) # regular resolution color map
for i in range(10):
    colorline(x,y,cmap='cubehelix', linewidth=1)

1 loops, best of 1: 532 ms per loop

如果您想要平滑的渐变并且只有几个点,那么按照当前选择的答案提供的方法,对线进行向上采样以获得更好的颜色渐变仍然是一个好主意。


我已经使用pcolormesh添加了解决方案
每个线段都使用一个矩形绘制,该矩形在两端的颜色之间进行插值。因此它确实是在插值颜色,但是我们必须传递线条的粗细。

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import numpy as np
import matplotlib.pyplot as plt

def colored_line(x, y, z=None, linewidth=1, MAP='jet'):
    # this uses pcolormesh to make interpolated rectangles
    xl = len(x)
    [xs, ys, zs] = [np.zeros((xl,2)), np.zeros((xl,2)), np.zeros((xl,2))]

    # z is the line length drawn or a list of vals to be plotted
    if z == None:
        z = [0]

    for i in range(xl-1):
        # make a vector to thicken our line points
        dx = x[i+1]-x[i]
        dy = y[i+1]-y[i]
        perp = np.array( [-dy, dx] )
        unit_perp = (perp/np.linalg.norm(perp))*linewidth

        # need to make 4 points for quadrilateral
        xs[i] = [x[i], x[i] + unit_perp[0] ]
        ys[i] = [y[i], y[i] + unit_perp[1] ]
        xs[i+1] = [x[i+1], x[i+1] + unit_perp[0] ]
        ys[i+1] = [y[i+1], y[i+1] + unit_perp[1] ]

        if len(z) == i+1:
            z.append(z[-1] + (dx**2+dy**2)**0.5)    
        # set z values
        zs[i] = [z[i], z[i] ]
        zs[i+1] = [z[i+1], z[i+1] ]

    fig, ax = plt.subplots()
    cm = plt.get_cmap(MAP)
    ax.pcolormesh(xs, ys, zs, shading='gouraud', cmap=cm)
    plt.axis('scaled')
    plt.show()

# create random data
N = 10
np.random.seed(101)
x = np.random.rand(N)
y = np.random.rand(N)
colored_line(x, y, linewidth = .01)

enter image description here


我正在使用@alexbw代码来绘制抛物线。效果很好。我可以更改功能的颜色集。为了进行计算,我花了大约1分钟30秒。我使用的是Intel i5,图形2GB,8GB内存。

代码如下:

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import numpy as np
import matplotlib.pyplot as plt
from matplotlib import cm
import matplotlib.collections as mcoll
import matplotlib.path as mpath

x = np.arange(-8, 4, 0.01)
y = 1 + 0.5 * x**2

MAP = 'jet'
NPOINTS = len(x)

fig = plt.figure()
ax1 = fig.add_subplot(111)
cm = plt.get_cmap(MAP)
for i in range(10):
    ax1.set_color_cycle([cm(1.0*i/(NPOINTS-1)) for i in range(NPOINTS-1)])
    for i in range(NPOINTS-1):
        plt.plot(x[i:i+2],y[i:i+2])

plt.title('Inner minimization', fontsize=25)
plt.xlabel(r'Friction torque $[Nm]$', fontsize=25)
plt.ylabel(r'Accelerations energy $[\frac{Nm}{s^2}]$', fontsize=25)
plt.show() # Show the figure

结果是:
https://i.stack.imgur.com/gL9DG.png