python 命名空间 | 码农家园

namespace on python pickle

我有一个错误，当我使用unittest泡菜。

3：我写的程序文件

一类是pickled，

这一类的类中使用# 1

在# unittest测试2级。

与真正的代码分别是为您。

# 1。classtopickle.py

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import pickle
class ClassToPickle(object):
def __init__(self, x):
self.x = x
if __name__=="__main__":
p = ClassToPickle(10)
pickle.dump(p, open('10.pickle', 'w'))

# 2。someclass.py

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from ClassToPickle import ClassToPickle
import pickle

class SomeClass(object):
def __init__(self):
self.pickle = pickle.load(open("10.pickle", 'r'))
self.x = self.pickle.x
print self.x

if __name__ =="__main__":
SomeClass()

# 3。someclasstest.py

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import unittest
from SomeClass import SomeClass
from ClassToPickle import ClassToPickle # REQUIRED_LINE

class SomeClassTest(unittest.TestCase):
def testA(self):
sc = SomeClass()
self.assertEqual(sc.x, 10)

def main():
unittest.main()

if __name__ =="__main__":
main()

我回答# 1第一个程序文件组成的泡菜。然后，当我运行程序文件#独立(2 IU回车"Python someclass.py")，它的工作原理。和，当我运行程序# 3独立的(即"Python someclasstest.py回车")，它的作品。

然而，当我运行程序# 3"单元测试"+ pydev Eclipse，它返回下面的错误消息。

======================================================================
ERROR: testA (SomeClassTest.SomeClassTest)
----------------------------------------------------------------------
Traceback (most recent call last):$ File
"/home/tmp/pickle_problem/SomeClassTest.py", line 9, in
testA
sc = SomeClass()$ File"/home/tmp/pickle_problem/SomeClass.py", line 8, in
init
self.pickle = pickle.load(open("10.pickle", 'r'))$ File"/usr/lib/python2.7/pickle.py", line 1378, in load
return Unpickler(file).load()$ File"/usr/lib/python2.7/pickle.py", line 858, in load
dispatchkey File"/usr/lib/python2.7/pickle.py", line 1090, in load_global
klass = self.find_class(module, name)$ File"/usr/lib/python2.7/pickle.py", line 1126, in find_class
klass = getattr(mod, name)$ AttributeError: 'module' object has no attribute 'ClassToPickle'
---------------------------------------------------------------------- Ran 1 test in 0.002s FAILED (errors=1)

当我和因此，该线是进口classtopickle out a(3类线#该计划为"必修3和_线")，它不工作和返回错误消息下面的描述。

E
======================================================================
ERROR: testA (main.SomeClassTest)
----------------------------------------------------------------------
Traceback (most recent call last):
File"SomeClassTest.py", line 9, in testA
sc = SomeClass()
File"/home/tmp/pickle_problem/SomeClass.py", line 8, in init
self.pickle = pickle.load(open("10.pickle", 'r'))
File"/usr/lib/python2.7/pickle.py", line 1378, in load
return Unpickler(file).load()
File"/usr/lib/python2.7/pickle.py", line 858, in load
dispatchkey
File"/usr/lib/python2.7/pickle.py", line 1090, in load_global
klass = self.find_class(module, name)
File"/usr/lib/python2.7/pickle.py", line 1126, in find_class
klass = getattr(mod, name)
AttributeError: 'module' object has no attribute 'ClassToPickle'

----------------------------------------------------------------------
Ran 1 test in 0.001s

FAILED (errors=1)

我想问题是关于命名空间在Python，但我不知道发生了什么事和什么是I do for分辨它。

Mi-24"运行单元测试(如Eclipse + pydev)"# 3程序正确，# 3程序和运行在命令行没有classtopickle线是进口的吗？请帮助我。