关于排序：如何根据函数返回的值对dart中的List进行排序

How to sort List in dart based on value returned by a function

我必须按最近的位置显示商店列表
我有一个未排序的商店列表和一个要计算的函数
每个商店到当前位置的距离，但我不知道如何
根据函数返回的值对dart中的List进行排序。
我从api获取未排序的商店数据列表。
对于这个问题，我需要逻辑来对_kikkleStores List

进行排序

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class KikkleStoresBloc extends BlocBase {
List<KikkleStoreInfo> _kikkleStores = [];
//for distance sorting
List<KikkleStoreInfo> _kikkleStoresSorted = [];
List<double> distanceFromCurrentLocation;//already got
value in it
bool hasReachedEndOfList = false;
Coordinate _currentLocation;

KikkleStoresBloc();

final _kikkleStoreSubject =
BehaviorSubject<List<KikkleStoreInfo>>
();

// Getter Stream
Stream<List<KikkleStoreInfo>> get kikkleStores =>
_kikkleStoreSubject.stream;`enter code here`

// Getter Sink
Function(List<KikkleStoreInfo>) get _fetchedkikkleStores =>
_kikkleStoreSubject.sink.add;

getKikkleStores() async {
try {
if (_currentPage <= _totalPages) {
final response = await
ApiController.getKikkleStores(_currentPage);
_kikkleStores.addAll(response.item1);

//here how to sort _kikkleStores by using
getStoreDistance function

_totalPages = response.item3;
_fetchedkikkleStores(_kikkleStores);
if (_currentPage == _totalPages) {
hasReachedEndOfList = true;
} else if (_currentPage < _totalPages &&
_kikkleStores.length
< 10) {

}
}
}
}

// this function returns distance
getStoreDistance(Coordinate currentLocation, KikkleStoreInfo
store)
async {
if (currentLocation == null) return 0.0;
try {
double distanceInMeter = await
LocationUtils.getDistanceInMeters(
currentLocation, Coordinate(store.latitude,
store.longitude));
// final miles = (distanceInMeter / 1609.344).round();
return distanceInMeter;
} catch (e) {
return 0.0;
}
}
void getCurrentLocation() async {
try {
final isAllowed = await
PermissionsUtils.isLocationAccessAllowed();
if (isAllowed) {
final coordinates = await
LocationUtils.getCurrentLocation();
if (coordinates != null) {
_currentLocation = coordinates;
}
}
}
catch (e) {
print(e);
}
}
}

参考以下代码

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void main(){
List<POJO> pojo = [POJO(5), POJO(3),POJO(7),POJO(1)];
// fill list

pojo..sort((a, b) => a.id.compareTo(b.id));
for(var i in pojo){
print(i.id); // prints list in sorted order i.e 1 3 5 7
}

}

class POJO {
int id;

POJO(this.id);
}