关于python：使用ipywidgets和plotly v4的Jupyter？

Jupyter with ipywidgets and plotly v4?

在Windows 10上使用Anaconda的Jupyter安装；还安装了conda install -c plotly plotly，并且显然安装了Plotly v4。

我只想从一个简单的示例开始-并使用ipywidget滑块而不是Plotly滑块。因此，我发现：

https://moderndata.plot.ly/widgets-in-ipython-notebook-and-plotly/

EXAMPLE 3: interact

A simple example of using the interact decorator from ipywidgets to create a simple set of widgets to control the parameters of a plot.

Link to IPython notebook

对-所以我转到了该链接，并将其中的代码重新组织为：

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import plotly.graph_objs as go
import numpy as np
from ipywidgets import interact

fig = go.FigureWidget()
scatt = fig.add_scatter()

xs=np.linspace(0, 6, 100)
fig.show()

@interact(a=(1.0, 4.0, 0.01), b=(0, 10.0, 0.01), color=['red', 'green', 'blue'])
def update(a=3.6, b=4.3, color='blue'):
with fig.batch_update():
scatt.x=xs
scatt.y=np.sin(a*xs-b)
scatt.line.color=color

...，当我运行此单元格时，它会绘制一个空图：

...，并失败：

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---------------------------------------------------------------------------
AttributeError Traceback (most recent call last)
C:\\ProgramData\\Anaconda3\\lib\\site-packages\\ipywidgets\\widgets\\interaction.py in update(self, *args)
254 value = widget.get_interact_value()
255 self.kwargs[widget._kwarg] = value
--> 256 self.result = self.f(**self.kwargs)
257 show_inline_matplotlib_plots()
258 if self.auto_display and self.result is not None:

<ipython-input-21-7dcd6b5f2be1> in update(a, b, color)
12 def update(a=3.6, b=4.3, color='blue'):
13 with fig.batch_update():
---> 14 scatt.x=xs
15 scatt.y=np.sin(a*xs-b)
16 scatt.line.color=color

C:\\ProgramData\\Anaconda3\\lib\\site-packages\\plotly\\basedatatypes.py in __setattr__(self, prop, value)
349 else:
350 # Raise error on unknown public properties
--> 351 raise AttributeError(prop)
352
353 def __getitem__(self, prop):

AttributeError: x

显然，这是因为Plotly v4中进行了足够的更改，以保证有版本4迁移指南|阴谋地通过浏览，我试图像这样修改代码：

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import plotly.graph_objs as go
import numpy as np
from ipywidgets import interact

fig = go.FigureWidget()
scattf = fig.add_scatter()
scatt = scattf.data[-1]

xs=np.linspace(0, 6, 100)
scattf.show()

@interact(a=(1.0, 4.0, 0.01), b=(0, 10.0, 0.01), color=['red', 'green', 'blue'])
def update(a=3.6, b=4.3, color='blue'):
with fig.batch_update():
scatt.x=xs
scatt.y=np.sin(a*xs-b)
scatt.line.color=color

...现在我不再收到错误-但是该图仍然为空，并且在拖动滑块时不会更新。

有人可以告诉我，如何使该示例正常工作，以便在拖动滑块时绘制图并进行更新/重绘？

编辑：有点混乱了，现在我有了这段代码：

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import plotly.graph_objs as go
import numpy as np
from ipywidgets import interact

fig = go.FigureWidget()
scattf = fig.add_scatter()
scatt = scattf.data[-1]

xs=np.linspace(0, 6, 100)
#scattf.show() # adds extra plot, if there is scattf.show() in update()!

@interact(a=(1.0, 4.0, 0.01), b=(0, 10.0, 0.01), color=['red', 'green', 'blue'])
def update(a=3.6, b=4.3, color='blue'):
with fig.batch_update():
scatt.x=xs
scatt.y=np.sin(a*xs-b)
scatt.line.color=color
scattf.show()

update() # update once; so we don't get empty plot at start? not really - still getting empty plot at start, and another one after which is updated

这里有两个问题：

运行单元格后，首先绘制一个空的图，然后绘制另一个图-如何获取仅绘制默认值的图？ (没有最后一个update()，只有一个图，但是开始时为空-必须拖动滑块使其开始绘制)
现在，在拖动滑块时，绘图会发生变化-但它会闪烁很多。有什么办法可以减少闪烁？

相关讨论

是的，因此找到了使用FigureWidget ipywidgets进行交互式数据分析-并相应地重写了示例；这具有更平滑的响应，并且不会出现两次抽签-但是，我仍然不确定这是否是这样做的方法；所以如果有人知道更好，请发表...

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import plotly.graph_objs as go
import numpy as np
#from ipywidgets import interact, interactive
from ipywidgets import widgets
from IPython.display import display

aSlider = widgets.FloatSlider(
value=2.0,
min=1.0,
max=4.0,
step=0.01,
description='a:',
continuous_update=False
)

bSlider = widgets.FloatSlider(
value=1.0,
min=0.0,
max=10.0,
step=0.01,
description='b:',
continuous_update=True
)

colorDropdown = widgets.Dropdown(
description='Color:',
value='blue',
options=['red', 'blue', 'green']
)

fig = go.FigureWidget()
#fig.show()
scattf = fig.add_scatter()
scatt = scattf.data[-1]

xs=np.linspace(0, 6, 100)

def response(change):
with fig.batch_update():
fig.data[0].x=xs
fig.data[0].y=np.sin(aSlider.value*xs-bSlider.value)
fig.data[0].line.color=colorDropdown.value
fig.layout.xaxis.title = 'whatever'

aSlider.observe(response, names="value")
bSlider.observe(response, names="value")
colorDropdown.observe(response, names="value")

response("doesn't matter what I send here, just triggering") # MUST be before widgets.VBox - if response(x) is last, NOTHING is drawn!

widgets.VBox([aSlider,
bSlider,
colorDropdown,
fig])