module 'django.contrib.auth.views' has no attribute 'login'
我运行:python manage.py migration并出现此错误
我认为对于此版本的Django,您需要重写代码,但我不知道该怎么做。
DJANGO 2.2
模块" django.contrib.auth.views"没有属性"登录"
我认为对于此版本的Django,您需要重写代码,但我不知道该怎么做。
这是我的代码:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 | File url.py [from django.conf.urls import url, include from django.contrib import admin from KisEats3app import views from django.contrib.auth import views as auth_views from django.conf.urls.static import static from django.conf import settings urlpatterns = \\[ url(r'^admin/', admin.site.urls), url(r'^$', views.home, name='home'), Restaurant url(r'^restaurant/sign-in/$', auth_views.login, {'template_name': 'restaurant/sign_in.html'}, name = 'restaurant-sign-in'), url(r'^restaurant/sign-out', auth_views.logout, {'next_page': '/'}, name = 'restaurant-sign-out'), url(r'^restaurant/sign-up', views.restaurant_sign_up, name = 'restaurant-sign-up'), url(r'^restaurant/$', views.restaurant_home, name = 'restaurant-home'), Sign In/ Sign Up/ Sign Out url(r'^api/social/', include('rest_framework_social_oauth2.urls')), /convert-token (sign in/ sign up) /revoke-token (sign out) \\] + static(settings.MEDIA_URL, document_root=settings.MEDIA_ROOT)][1] |
用
1 2 3 4 | from django.contrib.auth.views import LoginView url(r'^restaurant/sign-in/$', LoginView.as_view(template_name='restaurant/sign_in.html'), name='restaurant-sign-in'), |
LoginView是一个基于类的视图,因此应使用... as_view()
在HTML中,您必须使用{{form.as_p}}来显示您的所有字段