关于php:如何连接四个表来显示具体数据

how to join four table to display specific data

我在加入表格时遇到了一些麻烦。我有四张桌子

"设备"表

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equipment_id   equipment_name
-----------    --------------
1              Motor Cycle
2              Private Car

==================================

这是我的项目表

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project_id    project_name
----------    ------------
1              xyz trading
2              abc private ltd

=================================

这是出租桌

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rental_id      project_id    equipment_id   Rental_date
---------------------------------------------------------
1                 2                 1         12/10/2018
2                 2                2          15/09/2018
3                 1                2          20/10/2018

这是删除表

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remove_id      project_id    equipment_id   removal_date
---------------------------------------------------------
1                 2                 1         null
2                 2                2         14/10/18

these are my table, now i want to display data of single equipment (eg: equipment no 2) in which project this equipment ran, when was the rental date and when was the removal date from a project.

我想这样显示..(使用 Codeigniter)

设备2日志

=======

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    SN   Project Name      Rental date       Removal date
    ---  ------------      -----------       ------------
    1    ABC pvt Ltd        15/09/2018       14/10/2018
    2    xyz trading        20/10/2018         Null

控制器传递给模型

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$data['eqipment_details']=$this->Equipment_model->getLog($equipment_id);

请帮我查询


不得不猜测你的表名是什么,但你应该能够从中调整:

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SELECT
(@cnt := @cnt + 1) AS SN,
PROJECT.project_name AS Project Name,
RENTAL.Rental_date AS Rental date,
REMOVAL.removal_date AS Removal date
FROM
rental_table RENTAL
LEFT JOIN project_table PROJECT ON (RENTAL.project_id = PROJECT.id)
LEFT JOIN equipment_table EQUIPMENT ON (RENTAL.equipment_id = EQUIPMENT.id)
LEFT JOIN removal_table REMOVAL ON (PROJECT.id = REMOVAL.project_id AND PROJECT.equipment_id = REMOVAL.equipment_id)
WHERE
EQUIPMENT.id = 2;

我强烈建议与您的命名约定保持一致,您将骆驼大小写和标题大小写与下划线混合。