Linux find files and folders based on name length but output full path
我有以下文件夹结构：
1 2 3 4 5 6 | ├── longdirectorywithsillylengththatyouwouldntnormallyhave │ ├── asdasdads9ads9asd9asd89asdh9asd9asdh9asd │ └── sinlf └── shrtdir ├── nowthisisalongfile0000000000000000000000000 └── sfile |
我需要找到文件和文件夹，它们的名称长度超过x个字符。我已经能够做到这一点：
1 2 3 | longdirectorywithsillylengththatyouwouldntnormallyhave asdasdads9ads9asd9asd89asdh9asd9asdh9asd nowthisisalongfile0000000000000000000000000 |
但是，这只输出相关文件或文件夹的名称。如何输出这样的结果匹配的完整路径：
1 2 3 | /home/user/Desktop/longdirectorywithsillylengththatyouwouldntnormallyhave /home/user/Desktop/longdirectorywithsillylengththatyouwouldntnormallyhave/asdasdads9ads9asd9asd89asdh9asd9asdh9asd /home/user/Desktop/shrtdir/nowthisisalongfile0000000000000000000000000 |
如果在文件上使用
因此，必须更改regex才能识别最后一个路径组件的长度。
我能想到的最简单的方法是：
1 | find . | egrep '[^/]{20,}$' | xargs readlink -f |
这利用了一个事实，即文件名不能包含斜杠。
因此，结果包含相对于您当前的
1 2 | find -name"????????????????????*" -printf"$PWD/%P " |
找到的-printf选项非常强大。%P：
1 | %P File's name with the name of the starting-point under which it was found removed. (%p starts with ./). |
所以我们在前面加上$pwd/。
1 2 3 | /home/stefan/proj/mini/forum/tmp/Mo/shrtdir/nowthisisalongfile0000000000000000000000000 /home/stefan/proj/mini/forum/tmp/Mo/longdirectorywithsillylengththatyouwouldntnormallyhave /home/stefan/proj/mini/forum/tmp/Mo/longdirectorywithsillylengththatyouwouldntnormallyhave/asdasdads9ads9asd9asd89asdh9asd9asdh9asd |
为了防止我们手动计算问号，我们使用：
1 2 | for i in {1..20}; do echo -n"?" ; done; echo ???????????????????? |
我现在不能测试它，但这应该可以做到：
1 | find $(pwd) -exec basename '{}' ';' | egrep '^.{20,}$' |