关于python：Python3’ascii’编解码器无法编码位置135-136的字符：序数不在范围内（128）

Python3 'ascii' codec can't encode characters in position 135-136: ordinal not in range(128)

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# -*- coding: utf-8 -*-
#!/usr/bin/python3
import smtplib

gmail_user = 'X@X'
gmail_password = 'XXX'

from_add = gmail_user
to = ["X@X"]
subject ="主旨(subject)"
body ="內容(content)"
email_text ="""\
From: %s
To: %s
Subject: %s
%s
"""%(from_add,",".join(to), subject, body)

try:
smtpObj = smtplib.SMTP('smtp.gmail.com', 587)
smtpObj.ehlo()
smtpObj.starttls()
smtpObj.login(gmail_user, gmail_password)
smtpObj.sendmail(from_add, to, email_text)
smtpObj.close()
print('Email sent')
except UnicodeEncodeError as err:
print('{}'.format(err))
except:
print("err")

我得到了单码编码错误：

"ascii"编解码器无法对位置73-74中的字符进行编码：序号不在范围内(128)

python3默认编码不是"utf-8"吗？？

当我运行这个脚本时

实际上是Python3.5.2

当我打印身体的类型时，它是str

但对于python2，错误似乎是asciicode而不是unicode。

谢谢

smtplib.SMTP.sendmail期望其msg参数为仅包含ASCII字符的str或bytes参数：

msg may be a string containing characters in the ASCII range, or a
byte string. A string is encoded to bytes using the ascii codec, and
lone
and
characters are converted to

characters. A byte
string is not modified.

您的消息是一个字符串，但包含非ASCII字符；您需要将其编码为字节：

smtpObj.sendmail(from_add, to, email_text.encode('utf-8'))