关于lua：LuaSocket服务器：accept()超时(TCP)

LuaSocket server:accept() timeout (TCP)

问题

按照LuaSocket的介绍，我设法使服务器运行。我还设法从客户端连接。但是，我注意到服务器脚本冻结，直到server:accept()获得连接。

研究

LuaSocket参考指定：

Use the settimeout method or accept might block until another client shows up.

甚至包括在示例代码中。但是，在local client = server:accept()之后调用client:settimeout(10)，因此脚本在到达这一点之前被阻塞。

我读到可以通过多线程解决此问题，但这似乎有点夸张。

问题

如何使服务器脚本停止等待连接并继续前进？

如何避免client:receive()(服务器端)和tcp:receive()(客户端)(或client:settimeout(10)负责)的类似问题？

码

服务器(来自LuaSocket简介)

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23

-- load namespace
local socket = require("socket")
-- create a TCP socket and bind it to the local host, at any port
local server = assert(socket.bind("*", 0))
-- find out which port the OS chose for us
local ip, port = server:getsockname()
-- print a message informing what's up
print("Please telnet to localhost on port" .. port)
print("After connecting, you have 10s to enter a line to be echoed")
-- loop forever waiting for clients
while 1 do
-- wait for a connection from any client
local client = server:accept()
-- make sure we don't block waiting for this client's line
client:settimeout(10)
-- receive the line
local line, err = client:receive()
-- if there was no error, send it back to the client
if not err then client:send(line .."\
") end
-- done with client, close the object
client:close()
end

客户(遵循此答案)

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15

local host, port ="127.0.0.1", 100
local socket = require("socket")
local tcp = assert(socket.tcp())

tcp:connect(host, port);
--note the newline below
tcp:send("hello world\
");

while true do
local s, status, partial = tcp:receive()
print(s or partial)
if status =="closed" then break end
end
tcp:close()

您应该能够在调用server:accept()之前使用server：timeout()：

1
2
3

server:settimeout(2)
local client, err = server:accept()
print(client, err)

如果2秒钟内没有请求，这将为我打印nil timeout。