关于php：类型定义字符串中的元素数量与绑定变量的数量不匹配

Number of elements in type definition string doesn't match number of bind variables

我一直在我的php文件中收到此错误。
警告：mysqli_stmt_bind_param()[function.mysqli-stmt-bind-param]：类型定义字符串中的元素数量与第17行上...中的绑定变量数量不匹配
这是我的代码-我正在尝试从该表中读取所有内容，并将每列(例如用户名或obo)存储到一个数组中，对于每个Thanks

，可能是一个完整的数组，也可能是单个的数组

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<?php
$con = mysqli_connect("*****","****","***","***");

$username = $_POST["username"];
$title = $_POST["title"];
$description = $_POST["description"];
$location = $_POST["location"];
$cost = $_POST["cost"];
$obo = $_POST["obo"];
$dimmension = $_POST["dimmension"];
$phone = $_POST["phone"];
$email = $_POST["email"];
$image = $_POST["image"];
$image2 = $_POST["image2"];

$statement = mysqli_prepare($con,"SELECT username,title,description,location,cost,obo,dimmension,phone,email,image,image2 FROM Postings");
mysqli_stmt_bind_param($statement, $username,$title,$description,$location,$cost,$obo,$dimmension,$phone,$email,$image,$image2);
mysqli_stmt_execute($statement);

mysqli_stmt_store_result($statement);
mysqli_stmt_bind_result($statement, $username,$title,$description,$location,$cost,$obo,$dimmension,$phone,$email,$image,$image2);

$response = array();

while(mysqli_stmt_fetch($statement)){
$response[] = $username;
}

$response["success"] = true;
#echo json_encode($respond);
echo json_encode($response);
?>

这里是我的php我的管理表的图片

enter