Swift string construction was too complex to be solved in reasonable time
这是我的代码：
1 2 3 4 5 6 7 8 9 | let request = NSMutableURLRequest(URL: NSURL(string:"http://www.example.com/submit.php")!) request.HTTPMethod ="POST" let postString ="user_name="+user_name+"&first_name="+first_name.text+"&last_name="+last_name.text+"&company_name="+company_name.text+"&location="+location.text+"&phone="+phone.text+"&website="+website.text+"&email="+email.text+"&about="+about.text request.HTTPBody = postString.dataUsingEncoding(NSUTF8StringEncoding) let task = NSURLSession.sharedSession().dataTaskWithRequest(request) { data, response, error in let responseString = NSString(data: data!, encoding: NSUTF8StringEncoding) print("responseString = \\(responseString)") } task.resume() |
当我尝试运行应用程序时，它在
Expression was too complex to be solved in reasonable time; consider breaking up the expression into distinct sub-expressions
尝试一下：
1 2 3 4 5 6 7 8 9 10 | let parameters = ["user_name" : user_name, "first_name" : first_name.text, "last_name" : last_name.text, "company_name" : company_name.text, "location" : location.text, "phone" : phone.text, "website" : website.text, "email" : email.text, "about" : about.text].map {"\\($0)=\\($1 ??"")" } let postString = parameters.joinWithSeparator("&") |
该解决方案将首先创建一个包含参数及其值的字典(这还将提高代码的可读性和可维护性)。
然后它将在该字典上执行"映射"，将其转换为包含
最后它将通过使用分隔符
连接数组中的所有字符串来创建一个字符串