Opengl Basic立方体图，但是立方体以单色绘制

Opengl Basic cube drawing, but cube draws in single color

我正在尝试绘制具有6种不同面颜色的5 * 5 * 5大小的立方体。但是，当我执行此操作时，它使用单色绘制，下面是多维数据集的代码。

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void init(void)
{
glClearColor(0,0,0,0);
glShadeModel(GL_FLAT);
}

void DrawCube(void)
{
glLoadIdentity();
gluLookAt(10, 10, 10, 0, 0, 0, 0, 1, 0);
glBegin(GL_POLYGON);

//face in xy plane
glColor3f(0.82, 0.41, 0.12);//this the color with which complete cube is drawn.
glVertex3f(0,0 ,0 );
glVertex3f(5, 0, 0);
glVertex3f(5, 5, 0);
glVertex3f(0, 5, 0);

//face in yz plane
glColor3f(1, 0, 0);
glVertex3f(0, 0, 0);
glVertex3f(0, 0, 5);
glVertex3f(0, 5, 0);
glVertex3f(0, 5, 5);

//face in zx plance
glColor3f(0, 1, 0);
glVertex3f(0, 0, 0 );
glVertex3f(0, 0, 5);
glVertex3f(5, 0, 5);
glVertex3f(5, 0, 0);

//|| to xy plane.
glColor3f(0, 0, 1);
glVertex3f(0, 0, 5);
glVertex3f(5, 0, 5);
glVertex3f(5, 5, 5);
glVertex3f(0, 5, 5);

//|| to yz plane
glColor3f(0.73, 0.58, 0.58);
glVertex3f(0,0 ,5 );
glVertex3f(5, 0, 5);
glVertex3f(5, 5, 5);
glVertex3f(0, 5, 5);

//|| to zx plane
glVertex3f(0.58, 0, 0.82);
glVertex3f(0, 5, 0 );
glVertex3f(0, 5, 5);
glVertex3f(5, 5, 5);
glVertex3f(5, 5, 0);
glEnd();
glFlush();
}

void reshape(int w,int h){

glViewport(0, 0, (GLsizei)w, (GLsizei)h);

glMatrixMode(GL_PROJECTION);
glLoadIdentity();
glFrustum(-1, 1, -1, 1, 1.5, 20);
glMatrixMode(GL_MODELVIEW);
}

int main(int argc, char** argv){

glutInit(&argc, argv);//we initizlilze the glut. functions
glutInitDisplayMode(GLUT_SINGLE|GLUT_RGB);
glutInitWindowPosition(100, 100);
glutCreateWindow(argv[0]);
init();
glutDisplayFunc(DrawCube);
glutReshapeFunc(reshape);
glutMainLoop();
return 0;
}

相关讨论

问题是

1	glBegin(GL_POLYGON);

这意味着以下所有顶点均属于同一凸多边形。

更改为

1	glBegin(GL_QUADS);

应该解决您的问题。

通常，绝对不要使用GL_POLYGON，因为它通常非常慢。

使用GL_QUADS，如果我没记错的话，如果所有顶点不在同一平面上，则GL_POLYGON可能具有未定义的行为。另外，将GL_SMOOTH用于阴影模型，我认为GL_FLAT会为整个脸部使用第一种颜色，再次，如果我没记错的话，已经有一段时间了。