org.hibernate.MappingException：无法确定：java.util.List的类型，在表：College，对于列：[org.hibernate.mapping.Column（students）]


org.hibernate.MappingException: Could not determine type for: java.util.List, at table: College, for columns: [org.hibernate.mapping.Column(students)]

现在，我正在学习Hibernate，并开始在我的项目中使用它。这是一个CRUD应用程序。我用冬眠来做所有的积垢手术。它对所有人都有效。但是，一对多，多对一，我已经厌倦了尝试。最后，它给出了下面的错误。

org.hibernate.MappingException: Could not determine type for: java.util.List, at table: College, for columns: [org.hibernate.mapping.Column(students)]

然后我又看了一遍这个视频教程。一开始对我来说很简单。但是，我做不到。现在也一样，说

org.hibernate.MappingException: Could not determine type for: java.util.List, at table: College, for columns: [org.hibernate.mapping.Column(students)]

我在互联网上进行了一些搜索，有人告诉它在休眠中有一个错误，有人说，通过添加@generetreatedvalue，这个错误将被清除。但对我来说没什么用，

我希望我能得到一些解决办法！！

谢谢！

这里是我的代码：

爪哇大学

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@Entity
public class College {
@Id
@GeneratedValue(strategy=GenerationType.AUTO)
private int collegeId;
private String collegeName;


private List<Student> students;

@OneToMany(targetEntity=Student.class, mappedBy="college", fetch=FetchType.EAGER)
public List<Student> getStudents() {
    return students;
}
public void setStudents(List<Student> students) {
    this.students = students;
}//Other gettters & setters omitted

学生JAVA

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@Entity
public class Student {


@Id
@GeneratedValue(strategy=GenerationType.AUTO)
private int studentId;
private String studentName;


private College college;

@ManyToOne
@JoinColumn(name="collegeId")
public College getCollege() {
    return college;
}
public void setCollege(College college) {
    this.college = college;
}//Other gettters & setters omitted

Main.java：

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public class Main {

private static org.hibernate.SessionFactory sessionFactory;

  public static SessionFactory getSessionFactory() {
    if (sessionFactory == null) {
      initSessionFactory();
    }
    return sessionFactory;
  }

  private static synchronized void initSessionFactory() {
    sessionFactory = new AnnotationConfiguration().configure().buildSessionFactory();

  }

  public static Session getSession() {
    return getSessionFactory().openSession();
  }

  public static void main (String[] args) {
                Session session = getSession();
        Transaction transaction = session.beginTransaction();
        College college = new College();
        college.setCollegeName("Dr.MCET");

        Student student1 = new Student();
        student1.setStudentName("Peter");

        Student student2 = new Student();
        student2.setStudentName("John");

        student1.setCollege(college);
        student2.setCollege(college);



        session.save(student1);
        session.save(student2);
        transaction.commit();
  }


}

慰问：

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 Exception in thread"main" org.hibernate.MappingException: Could not determine type  for: java.util.List, at table: College, for columns:  [org.hibernate.mapping.Column(students)]
at org.hibernate.mapping.SimpleValue.getType(SimpleValue.java:306)
at org.hibernate.mapping.SimpleValue.isValid(SimpleValue.java:290)
at org.hibernate.mapping.Property.isValid(Property.java:217)
at org.hibernate.mapping.PersistentClass.validate(PersistentClass.java:463)
at org.hibernate.mapping.RootClass.validate(RootClass.java:235)
at org.hibernate.cfg.Configuration.validate(Configuration.java:1330)
at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1833)
at test.hibernate.Main.initSessionFactory(Main.java:22)
at test.hibernate.Main.getSessionFactory(Main.java:16)
at test.hibernate.Main.getSession(Main.java:27)
at test.hibernate.Main.main(Main.java:43)

XML：

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<?xml version='1.0' encoding='utf-8'?>
<!DOCTYPE hibernate-configuration PUBLIC
"-//Hibernate/Hibernate Configuration DTD 3.0//EN"
"http://hibernate.sourceforge.net/hibernate-configuration-3.0.dtd">
<hibernate-configuration>
<session-factory>
    <!-- Database connection settings -->
    <property name="connection.driver_class">com.mysql.jdbc.Driver</property>
    <property name="connection.url">jdbc:mysql://localhost:3306/dummy</property>
    <property name="connection.username">root</property>
    <property name="connection.password">1234</property>
    <!-- JDBC connection pool (use the built-in) -->
    <property name="connection.pool_size">1</property>
    <!-- SQL dialect -->
    <property name="dialect">org.hibernate.dialect.MySQLDialect</property>
    <!-- Enable Hibernate's automatic session context management -->
    <property name="current_session_context_class">thread</property>
    <!-- Disable the second-level cache -->
    <property name="cache.provider_class">org.hibernate.cache.NoCacheProvider</property>
    <!-- Echo all executed SQL to stdout -->
    <property name="show_sql">true</property>
    <!-- Drop and re-create the database schema on startup -->
    <property name="hbm2ddl.auto">update</property>

    <mapping class="test.hibernate.Student" />
    <mapping class="test.hibernate.College" />
</session-factory>
相关讨论

您正在使用字段访问策略(由@id annotation确定)。在每个字段的正上方放置任何与JPA相关的注释，而不是getter属性

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@OneToMany(targetEntity=Student.class, mappedBy="college", fetch=FetchType.EAGER)
private List<Student> students;
相关讨论

在列表字段中添加@ElementCollection解决了这个问题：

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    @Column
    @ElementCollection(targetClass=Integer.class)
    private List<Integer> countries;
相关讨论

访问策略问题

As a JPA provider, Hibernate can introspect both the entity attributes
(instance fields) or the accessors (instance properties). By default,
the placement of the @Id annotation gives the default access
strategy. When placed on a field, Hibernate will assume field-based
access. Placed on the identifier getter, Hibernate will use
property-based access.

基于字段的访问

当使用基于字段的访问时，添加其他实体级别的方法更加灵活，因为Hibernate不会考虑持久性状态的那些部分。

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@Entity
public class Simple {

@Id
private Integer id;

@OneToMany(targetEntity=Student.class, mappedBy="college",
fetch=FetchType.EAGER)
private List<Student> students;

//getter +setter
}

基于属性的访问

使用基于属性的访问时，Hibernate将访问器用于读取和写入实体状态

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@Entity
public class Simple {

private Integer id;
private List<Student> students;

@Id
public Integer getId() {
    return id;
}

public void setId( Integer id ) {
    this.id = id;
}
@OneToMany(targetEntity=Student.class, mappedBy="college",
fetch=FetchType.EAGER)
public List<Student> getStudents() {
   return students;
}
public void setStudents(List<Student> students) {
    this.students = students;
}

}

但不能同时使用基于字段和基于属性的访问。它会对你显示出那样的错误

想了解更多的想法，请遵循以下步骤

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@Access(AccessType.PROPERTY)
@OneToOne(cascade = CascadeType.ALL, fetch = FetchType.EAGER)
@JoinColumn(name="userId")
public User getUser() {
    return user;
}

我也有同样的问题，我通过添加@Access(AccessType.PROPERTY)解决了它。

相关讨论

虽然我刚开始冬眠，但几乎没有什么研究(我们可以说是反复试验)我发现这是由于在注释方法/文件时不一致造成的。

在变量上注释@id时，请确保所有其他注释也仅在变量上完成。当您在getter方法上注释它时，同样要确保只注释所有其他getter方法，而不是它们各自的变量。

别担心！出现此问题是因为注释。与基于字段的访问不同，基于属性的访问解决了这个问题。代码如下：

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package onetomanymapping;

import java.util.List;

import javax.persistence.*;

@Entity
public class College {
private int collegeId;
private String collegeName;
private List<Student> students;

@OneToMany(targetEntity = Student.class, mappedBy ="college",
    cascade = CascadeType.ALL, fetch = FetchType.EAGER)
public List<Student> getStudents() {
    return students;
}

public void setStudents(List<Student> students) {
    this.students = students;
}

@Id
@GeneratedValue
public int getCollegeId() {
    return collegeId;
}

public void setCollegeId(int collegeId) {
    this.collegeId = collegeId;
}

public String getCollegeName() {
    return collegeName;
}

public void setCollegeName(String collegeName) {
    this.collegeName = collegeName;
}

}