关于python：’PySide.QtCore.Signal’对象没有属性’connect’

'PySide.QtCore.Signal' object has no attribute 'connect'

我将Python 3.4与Pyside 1.2.4和PyQt 4.8.7结合使用，当我尝试将Signal连接到插槽时，它说：

'PySide.QtCore.Signal' object has no attribute 'connect'

我正在使用MVC：

模型：

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from PySide.QtCore import Signal
class Model(object):

def __init__(self):
self.updateProgress = Signal(int)

控制器：

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class Controller(QWidget):
"""
MVC Pattern: Represents the controller class

"""
def __init__(self, parent=None):
super().__init__(parent)
self.model = Model()
self.model.updateProgress.connect(self.setProgress)

当我在Pycharm中查找类时，按住CTRL并单击Signal类，它看起来如下所示：

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class Signal(object):
""" Signal"""
def __call__(self, *args, **kwargs): # real signature unknown
""" Call self as a function."""
pass

def __getitem__(self, *args, **kwargs): # real signature unknown
""" Return self[key]."""
pass

def __init__(self, *args, **kwargs): # real signature unknown
pass

@staticmethod # known case of __new__
def __new__(*args, **kwargs): # real signature unknown
""" Create and return a new object. See help(type) for accurate signature."""
pass

def __str__(self, *args, **kwargs): # real signature unknown
""" Return str(self)."""
pass

...虽然实际上应该有根据PySide文档进行连接，断开连接和发出方法的方法，该方法可在以下位置获得：

https://srinikom.github.io/pyside-docs/PySide/QtCore/Signal.html#PySide.QtCore.Signal.connect

谢谢您的帮助

信号必须在类而不是实例上定义。该类必须是QObject的子类，或者是此类的mixin。因此，以下任何一项：

1 2	class Model(QtCore.QObject): updateProgress = Signal(int)

要么：

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class Mixin(object):
updateProgress = Signal(int)

class Model(Mixin, QtCore.QObject):
pass