关于C#：检查圆内还是圆外的点(仅通过结构实现)

Check whether a point inside or outside a circle (implementation with structs only)

首先，我给了一个任务，仅使用结构体来实现。

我需要检查一个点是否在圆的内部/外部。

输入：点，圆心，半径的坐标。

输出：是圆内/外的点。

好吧，我需要使用距离公式d = sqrt( (x_1-x_2)^2 + (y_1 - y_2)^2 )，然后检查它是否大于/小于/等于半径。

我知道逻辑，但是使用struct的语法失败。你们可以帮我吗？

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#include <stdio.h>
#include <stdlib.h>
#include <conio.h>

typedef struct {
float x;
float y;
}Point;

typedef struct {
Point center;
float radius;
}Circle;

int main()
{
Point Coordinates;
Coordinates.x = 0; //Is this initialization necessary?
Coordinates.y = 0; //Is this initialization necessary?
Circle insideCircle;
float distance;
printf("Please enter the coordinates of your point:");
scanf("%f %f", Coordinates.x, Coordinates.y); //after input, throws error.
printf("Please enter your center coordinate and your radius:");
scanf("%f %f", insideCircle.radius, insideCircle.center.x, insideCircle.center.y);
printf("%f %f %f %f %f", Coordinates.x, Coordinates.y, insideCircle.radius, insideCircle.center.x, insideCircle.center.y);

//More code for checking if distance > or < or = to radius to be added.
getch();
}

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/*i think this piece of code will help you*/

#include <stdio.h>
#include <stdlib.h>

typedef struct {
float x;
float y;
}Point;

typedef struct {
Point center;
float radius;
}Circle;

int main()
{
Point Coordinates;
Coordinates.x = 0;
Coordinates.y = 0;
Circle insideCircle;
float distance;
printf("Please enter the coordinates of your point:");
scanf("%f %f", &(Coordinates.x), &(Coordinates.y) ); //scanf requires &
printf("Please enter your center coordinate and your radius:");
scanf("%f %f %f", &(insideCircle.radius), &(insideCircle.center.x), &(insideCircle.center.y) );//scanf requires &
printf("%f %f %f %f %f", Coordinates.x, Coordinates.y, insideCircle.radius, insideCircle.center.x, insideCircle.center.y);

//More code for checking if distance > or < or = to radius to be added.
}