创建一个python scrabble函数，它将一个字符串作为输入并返回该单词的分数

Creating a python scrabble function that takes a string as input and returns a score for that word

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嗨，我正在编解码器练习9/15。目标是创建一个以字符串作为输入的拼字函数，然后返回该单词的分数。

他们给你一本字典作为开始，这是我在谷歌上搜索"如何循环使用字典并添加值"后得到的。

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score = {"a": 1,"c": 3,"b": 3,"e": 1,"d": 2,"g": 2,
"f": 4,"i": 1,"h": 4,"k": 5,"j": 8,"m": 3,
"l": 1,"o": 1,"n": 1,"q": 10,"p": 3,"s": 1,
"r": 1,"u": 1,"t": 1,"w": 4,"v": 4,"y": 4,
"x": 8,"z": 10}

1) total = 0 # takes your input word value and saves it to total

2) def scrabble_score(x): # defining function name
3) for i in score.values(): # loops through score
4) total += i # sums up your input key value
5) return i

此代码不断引发局部变量total错误。

这是否意味着总变量不适用于拼字得分(x)函数？

相关讨论

你需要把total = 0放在函数中，你需要循环输入单词，然后从字典中添加每个字母的分数。您还需要返回total，而不是i。

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SCORES = {"a": 1,"c": 3,"b": 3,"e": 1,"d": 2,"g": 2,
"f": 4,"i": 1,"h": 4,"k": 5,"j": 8,"m": 3,
"l": 1,"o": 1,"n": 1,"q": 10,"p": 3,"s": 1,
"r": 1,"u": 1,"t": 1,"w": 4,"v": 4,"y": 4,
"x": 8,"z": 10}

def scrabble_score(word):
total = 0
for letter in word:
total += SCORES[letter]
return total

另一种方法是，记住未来：

1 2	def scrabble_score(word): return sum(SCORES[letter] for letter in word)