关于python：如何在BaseHTTPRequestHandler子类中停止BaseHTTPServer.serve_forever()？

How to stop BaseHTTPServer.serve_forever() in a BaseHTTPRequestHandler subclass?

我在单独的线程中运行HTTPServer(使用无法停止线程的线程模块...)，并且想在主线程也关闭时停止提供请求。

Python文档指出BaseHTTPServer.HTTPServer是SocketServer.TCPServer的子类，它支持shutdown方法，但在HTTPServer中丢失。

整个BaseHTTPServer模块只有很少的文档:(

我首先要说："我自己可能不会做，但过去我会做。" serve_forever(来自SocketServer.py)方法如下所示：

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def serve_forever(self):
"""Handle one request at a time until doomsday."""
while 1:
self.handle_request()

您可以将while 1(在子类中)替换为while self.should_be_running，然后从其他线程修改该值。就像是：

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def stop_serving_forever(self):
"""Stop handling requests"""
self.should_be_running = 0
# Make a fake request to the server, to really force it to stop.
# Otherwise it will just stop on the next request.
# (Exercise for the reader.)
self.make_a_fake_request_to_myself()

编辑：我挖出了我当时使用的实际代码：

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class StoppableRPCServer(SimpleXMLRPCServer.SimpleXMLRPCServer):

stopped = False
allow_reuse_address = True

def __init__(self, *args, **kw):
SimpleXMLRPCServer.SimpleXMLRPCServer.__init__(self, *args, **kw)
self.register_function(lambda: 'OK', 'ping')

def serve_forever(self):
while not self.stopped:
self.handle_request()

def force_stop(self):
self.server_close()
self.stopped = True
self.create_dummy_request()

def create_dummy_request(self):
server = xmlrpclib.Server('http://%s:%s' % self.server_address)
server.ping()

相关讨论

在我的python 2.6安装中，我可以在基础TCPServer上调用它-它仍然在HTTPServer内部：

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TCPServer.shutdown

>>> import BaseHTTPServer
>>> h=BaseHTTPServer.HTTPServer(('',5555), BaseHTTPServer.BaseHTTPRequestHandler)
>>> h.shutdown
<bound method HTTPServer.shutdown of <BaseHTTPServer.HTTPServer instance at 0x0100D800>>
>>>

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基于http://docs.python.org/2/library/basehttpserver.html#more-examples的另一种实现方法是：只要满足条件，就继续提供服务，而不是serve_forever()。服务器在每个请求之前和之后检查条件。例如：

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import CGIHTTPServer
import BaseHTTPServer

KEEP_RUNNING = True

def keep_running():
return KEEP_RUNNING

class Handler(CGIHTTPServer.CGIHTTPRequestHandler):
cgi_directories = ["/cgi-bin"]

httpd = BaseHTTPServer.HTTPServer(("", 8000), Handler)

while keep_running():
httpd.handle_request()

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我认为您可以使用[serverName].socket.close()

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事件循环在SIGTERM，Ctrl + C或调用shutdown()时结束。

必须在server_forever()之后调用server_close()，以关闭监听套接字。

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import http.server

class StoppableHTTPServer(http.server.HTTPServer):
def run(self):
try:
self.serve_forever()
except KeyboardInterrupt:
pass
finally:
# Clean-up server (close socket, etc.)
self.server_close()

可通过用户操作停止简单服务器(SIGTERM，Ctrl + C等)：

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server = StoppableHTTPServer(("127.0.0.1", 8080),
http.server.BaseHTTPRequestHandler)
server.run()

服务器在线程中运行：

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import threading

server = StoppableHTTPServer(("127.0.0.1", 8080),
http.server.BaseHTTPRequestHandler)

# Start processing requests
thread = threading.Thread(None, server.run)
thread.start()

# ... do things ...

# Shutdown server
server.shutdown()
thread.join()

在python 2.7中，仅当您通过serve_forever服务时才调用shutdown()有效，因为它使用了异步选择和轮询循环。具有讽刺意味的是，使用handle_request()运行您自己的循环会排除此功能，因为这意味着一个愚蠢的阻塞调用。

从SocketServer.py的BaseServer中：

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def serve_forever(self, poll_interval=0.5):
"""Handle one request at a time until shutdown.

Polls for shutdown every poll_interval seconds. Ignores
self.timeout. If you need to do periodic tasks, do them in
another thread.
"""
self.__is_shut_down.clear()
try:
while not self.__shutdown_request:
# XXX: Consider using another file descriptor or
# connecting to the socket to wake this up instead of
# polling. Polling reduces our responsiveness to a
# shutdown request and wastes cpu at all other times.
r, w, e = select.select([self], [], [], poll_interval)
if self in r:
self._handle_request_noblock()
finally:
self.__shutdown_request = False
self.__is_shut_down.set()

这是我的代码的一部分，用于使用事件等待完成来阻止其他线程关闭：

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class MockWebServerFixture(object):
def start_webserver(self):
"""
start the web server on a new thread
"""
self._webserver_died = threading.Event()
self._webserver_thread = threading.Thread(
target=self._run_webserver_thread)
self._webserver_thread.start()

def _run_webserver_thread(self):
self.webserver.serve_forever()
self._webserver_died.set()

def _kill_webserver(self):
if not self._webserver_thread:
return

self.webserver.shutdown()

# wait for thread to die for a bit, then give up raising an exception.
if not self._webserver_died.wait(5):
raise ValueError("couldn't kill webserver")

我成功使用了此方法(Python 3)从Web应用程序本身(网页)停止服务器：

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import http.server
import os
import re

class PatientHTTPRequestHandler(http.server.SimpleHTTPRequestHandler):
stop_server = False
base_directory ="/static/"
# A file to use as an"server stopped user information" page.
stop_command ="/control/stop.html"
def send_head(self):
self.path = os.path.normpath(self.path)
if self.path == PatientHTTPRequestHandler.stop_command and self.address_string() =="127.0.0.1":
# I wanted that only the local machine could stop the server.
PatientHTTPRequestHandler.stop_server = True
# Allow the stop page to be displayed.
return http.server.SimpleHTTPRequestHandler.send_head(self)
if self.path.startswith(PatientHTTPRequestHandler.base_directory):
return http.server.SimpleHTTPRequestHandler.send_head(self)
else:
return self.send_error(404,"Not allowed","The path you requested is forbidden.")

if __name__ =="__main__":
httpd = http.server.HTTPServer(("127.0.0.1", 8080), PatientHTTPRequestHandler)
# A timeout is needed for server to check periodically for KeyboardInterrupt
httpd.timeout = 1
while not PatientHTTPRequestHandler.stop_server:
httpd.handle_request()

这样，默认处理程序将为通过基地址http://localhost:8080/static/(例如http://localhost:8080/static/styles/common.css)提供的页面提供服务，从服务器计算机访问http://localhost:8080/control/stop.html的信息将显示为stop.html，然后停止服务器，其他任何选项为禁止的。

相关讨论

我尝试了上述所有可能的解决方案，最终遇到了"有时"问题-某种程度上它并没有真正做到-因此我最终做出了一个肮脏的解决方案，该解决方案一直对我有用：

如果以上所有方法均失败，则使用以下类似方法强行杀死线程：

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import subprocess
cmdkill ="kill $(ps aux|grep '<name of your thread> true'|grep -v 'grep'|awk '{print $2}') 2> /dev/null"
subprocess.Popen(cmdkill, stdout=subprocess.PIPE, shell=True)

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