关于python：UnboundLocalError当变量显然是本地的

UnboundLocalError when variable is clearly local

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我有一个类似的程序：

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curpuz = 1

def puzzle(req,_):
puzzledat = json.loads(open('puzzles.txt','r').read())
puzzleque = puzzledat[str(curpuz)]['q']
req.say('Current puzzle: ' + puzzleque + ' - !ans ')

def puzzlea(req,arg):
puzzledat = json.loads(open('puzzles.txt','r').read())
puzzleans = puzzledat[str(curpuz)]['a']
if arg[0] == puzzleans:
req.say('%tip ' + req.nick + ' 50 -- ' + req.nick + ' got the correct answer! Use !puzzle to get the next puzzle!')
try:
puzzledat = json.loads(open('puzzles.txt','r').read())
curpuz += 1
puzzleque = puzzledat[str(curpuz)]['q']
puzzleans = puzzledat[str(curpuz)]['a']
except:
req.say("Uh oh no more puzzles :(")
puzzleans = 'no more'
else:
req.reply('Incorrect')

但我继续得到一个UnboundLocalError("local variable 'curpuz' referenced before assignment",)，即使变量显然是局部的。