如何在python中将数组的所有元素添加到一个列表中

how to add all array's elements to one list in python

本问题已经有最佳答案，请猛点这里访问。

使用类似于此的二维数组：

1	myarray = [['jacob','mary'],['jack','white'],['fantasy','clothes'],['heat','abc'],['edf','fgc']]

每个元素都是一个具有固定长度元素的数组。如何成为这个人，

1	mylist = ['jacob','mary','jack','white','fantasy','clothes','heat','abc','edf','fgc']

这是我的解决方法

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mylist = []
for x in myarray:
mylist.extend(x)

我想应该更简单些

使用itertools.chain.from_iterable：

1 2	from itertools import chain mylist = list(chain.from_iterable(myarray))

演示：

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>>> from itertools import chain
>>> myarray = [['jacob','mary'],['jack','white'],['fantasy','clothes'],['heat','abc'],['edf','fgc']]
>>> list(chain.from_iterable(myarray))
['jacob', 'mary', 'jack', 'white', 'fantasy', 'clothes', 'heat', 'abc', 'edf', 'fgc']

然而，haidro’s解决方案是为您的sum()更快更短的样本：

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>>> timeit.timeit('f()', 'from __main__ import withchain as f')
2.858742465992691
>>> timeit.timeit('f()', 'from __main__ import withsum as f')
1.6423718839942012
>>> timeit.timeit('f()', 'from __main__ import withlistcomp as f')
2.0854451240156777

但是，如果输入itertools.chain赢得较大的有：

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>>> myarray *= 100
>>> timeit.timeit('f()', 'from __main__ import withchain as f', number=25000)
1.6583486960153095
>>> timeit.timeit('f()', 'from __main__ import withsum as f', number=25000)
23.100156371016055
>>> timeit.timeit('f()', 'from __main__ import withlistcomp as f', number=25000)
2.093297885992797