How do I do a deep copy of a 2d array in Java?
我只是在2d
如何执行
我应该遍历它并执行一系列
是的,您应该遍历2D布尔数组以进行深复制。如果您使用的是Java 6,也请查看
我建议使用Java 6的下一个代码:
1 2 3 4 5 6 7 8 9 10 11 12 13 | public static boolean[][] deepCopy(boolean[][] original) { if (original == null) { return null; } final boolean[][] result = new boolean[original.length][]; for (int i = 0; i < original.length; i++) { result[i] = Arrays.copyOf(original[i], original[i].length); // For Java versions prior to Java 6 use the next: // System.arraycopy(original[i], 0, result[i], 0, original[i].length); } return result; } |
在Java 8中,可以使用lambdas作为单行代码实现:
1 2 3 | < T > T[][] deepCopy(T[][] matrix) { return java.util.Arrays.stream(matrix).map(el -> el.clone()).toArray($ -> matrix.clone()); } |
我是Arrays实用程序的粉丝。它具有copyOf方法,该方法将为您完成一维数组的深层复制,因此您需要以下内容:
1 2 3 4 | //say you have boolean[][] foo; boolean[][] nv = new boolean[foo.length][foo[0].length]; for (int i = 0; i < nv.length; i++) nv[i] = Arrays.copyOf(foo[i], foo[i].length); |
我设法提出了一个递归数组深层副本。即使对于维度长度不同的多维数组,例如
1 2 3 4 5 6 7 8 9 10 11 12 13 14 | private static final int[][][] INT_3D_ARRAY = { { {1} }, { {2, 3}, {4, 5} }, { {6, 7, 8}, {9, 10, 11}, {12, 13, 14} } }; |
这是实用程序方法。
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 | @SuppressWarnings("unchecked") public static < T > T[] deepCopyOf(T[] array) { if (0 >= array.length) return array; return (T[]) deepCopyOf( array, Array.newInstance(array[0].getClass(), array.length), 0); } private static Object deepCopyOf(Object array, Object copiedArray, int index) { if (index >= Array.getLength(array)) return copiedArray; Object element = Array.get(array, index); if (element.getClass().isArray()) { Array.set(copiedArray, index, deepCopyOf( element, Array.newInstance( element.getClass().getComponentType(), Array.getLength(element)), 0)); } else { Array.set(copiedArray, index, element); } return deepCopyOf(array, copiedArray, ++index); } |
编辑:更新了代码以使用基本数组。
是的,这是唯一的方法。
这是一个使用
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 | package mcve.util; import java.lang.reflect.*; public final class Tools { private Tools() {} /** * Returns a copy of the specified array object, deeply copying * multidimensional arrays. If the specified object is null, the * return value is null. Note: if the array object has an element * type which is a reference type that is not an array type, the * elements themselves are not deep copied. This method only copies * array objects. * * @param array the array object to deep copy * @param < T > the type of the array to deep copy * @return a copy of the specified array object, deeply copying * multidimensional arrays, or null if the object is null * @throws IllegalArgumentException if the specified object is not * an array */ public static < T > T deepArrayCopy(T array) { if (array == null) return null; Class< ? > arrayType = array.getClass(); if (!arrayType.isArray()) throw new IllegalArgumentException(arrayType.toString()); int length = Array.getLength(array); Class< ? > componentType = arrayType.getComponentType(); @SuppressWarnings("unchecked") T copy = (T) Array.newInstance(componentType, length); if (componentType.isArray()) { for (int i = 0; i < length; ++i) Array.set(copy, i, deepArrayCopy(Array.get(array, i))); } else { System.arraycopy(array, 0, copy, 0, length); } return copy; } } |
您可以遍历此数组并执行一系列
1 2 3 4 5 6 7 8 9 10 11 | boolean[][] arr1 = {{true, true}, {false, true}}; // original array boolean[][] arr2 = Arrays.copyOf(arr1, arr1.length); // shallow copy boolean[][] arr3 = Arrays.stream(arr1) // deep copy .map(arr -> Arrays.copyOf(arr, arr.length)) .toArray(boolean[][]::new); arr1[0][0] = false; System.out.println(Arrays.deepToString(arr1)); // [[false, true], [false, true]] System.out.println(Arrays.deepToString(arr2)); // [[false, true], [false, true]] System.out.println(Arrays.deepToString(arr3)); // [[true, true], [false, true]] |
或者您可以调用
1 2 3 |
或者您可以为此创建通用方法:
1 2 3 4 5 | static < T > T[][] deepCopy(T[][] matrix) { return Arrays.stream(matrix) .map(arr -> arr.clone()) .toArray(s -> matrix.clone()); } |
另请参阅:在2D数组的情况下,为什么Array.copyOf()会使原始数组变异?