如何在C数组字符串中选择5位随机数？

How to select 5 digit random in C# Array String?

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Possible Duplicate:
How can I generate random 8 character, alphanumeric strings in C#?

我有一个以字母命名的数组，现在我需要随机选择5个字符，如果我使用下面的代码，我只能选择一个字符，如何随机选择给定数组字符串中的5个数字？

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String[] letters = {"1","2","3","4","5","6","7","8","9","0","A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q" };
Random rand = new Random();
String number = letters[rand.Next(1,10)];

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string number =
string.Concat(Enumerable.Range(0,5).Select(i =>
letters[rand.Next(0, 10)]));

当然，考虑到数组内容，这在功能上等同于：

1	string number = rand.Next(0, 100000).ToString("D5");

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string[] selected = new string[5];
Random rand = new Random();
for(int i = 0 ; i < selected.Length ; i++)
{
selected[i] = letters[rand.Next(letters.Length)];
}

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1	var randomSelection = (from c in letters orderby rand.Next() select c).Take(5);

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